Re: [Signal handler] Bug or feature ?

[BERTRAND Joël <joel.bertrand%systella.fr@localhost>]

Pongthep Kulkrisada a écrit :
> * BERTRAND Jol (joel.bertrand%systella.fr@localhost) wrote:
> > volatile int flag;
> >
> > flag = 0;
> >
> > do
> > {
> >         code_retour = nanosleep(&temporisation,&temporisation);
> >         erreur = errno;
> >
> >         if (flag == 1)
> >         {
> >                 exit(0);
> >         }
> > } while((code_retour == -1)&&  (erreur == EINTR));
> >
> > SIGINT signal handler is :
> >
> > void
> > interruption1(int signal)
> > {
> >         flag = 1;
> >         return;
> > }
> >
> > When this process receives SIGINT, it doesn't exit. I have verified
> > that signal handler is called and it is.
> If there is nothing wrong, it is very strange.
> I tried coding exactly what you did.
> On my 6.0_RC2 (i386), it does ``exit'' after SIGINT delivered to the process.

	I have tested on 5.1.2 (amd64) and this test program is linked with 
-pthread.

> > But nanosleep() returns with EINTR error before signal handler is called.
> On my machine, I can verify that signal handler is called before nanosleep() 
> returns.

	Not on mine. Even thread id is different between signal handler and 
main program.

        I have found a workaround. Thus I consider this post closed.

        Thanks a lot,

        JKB