Re: full-disc partition

[Edgar Fuß <ef%math.uni-bonn.de@localhost>]

So to correct myself:

> It looks that I remember incorrectly what ws@ taught me back in the days
> how the ``full disc'' partition works.
I just called him on the phone and the correct answer is that the code reading
the disklabel enforces the ``full disc'' partition to be the full disc.
Also that code seems to be able to return values >2^32 although the disklabel
itself cannot store them.