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Re: Arithmetic Expansion in shell.



On Fri, 8 Aug 2008, Glen Johnson wrote:
NetBSD-users,
I am trying to understand what I am doing wrong when using sh but not ksh.
In /bin/ksh I type:
echo $(( i=i+1 ))
I get the next value for i.

In /bin/sh ,  I type the same thing:
echo $(( i=i+1 ))
I get this;  arith: syntax error: " i=i+1 "

Why do you have i= at the start? That's an invalid expression.

--
Stephen



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