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On Sep 13, 2004, at 11:55 AM, Arto Huusko wrote:

> No. One of the properties of UTF-8 is that all the octets in an
> UTF-8 character that is encoded using multiple octets have their
> highest bit set.

Ah, I didn't realize that *all* of the octets in such a sequence were 
so encoded.

So, ignore my previous "I wonder how..." question and comment about the 
kernel :-)

         -- Jason R. Thorpe <thorpej@wasabisystems.com>


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