>> I've never understood why char ** is incompatible with
>> const char **....
> Briefly, [...]
> "const char *" is a different type from "char *", thus converting
> from "char **" to "const char **" is corresponding to (3).

Well, yes; what I mean is, I don't understand why they picked rules
that ended up with that effect.  It should be possible to add
qualifiers at any depth without producing an incompatible type.

> System A declares foo() as: void foo(char **);
> System B declares foo() as: void foo(const char **);

> If we wish to call it without warnings, we need to write as: [#if]

Or, actually,

	foo((void *)&str);

provided both systems provide prototypes.

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