> >>> #define	__DECONST(type, var)	((type)(uintptr_t)(const void *)(var))
> >> Why cast to a specific type?
> > because it's only sane way without typeof().
> 
> What's insane about just making it produce a void *?

- in most cases, what you want is a specific type, isn't it?

- it strips out other qualifiers like volatile.
  (typeof() isn't enough for this either.)

YAMAMOTO Takashi