briggs@netbsd.org wrote: 

> On Wed, Mar 02, 2005 at 04:33:16PM -0800, ALeine wrote:
> > elric@imrryr.org wrote: 
> > > It is _plainly_obvious_ that if you encrypt 2^30 sectors each
> > > with a different 128 bit key then there are at most 2^158
> > > different
> > > ways to decrypt the entire disk.	Period.
> > 
> > out which of the 2^128^(2^30) sector variations is the right
> one?
> 
> Which, I think, is 2^(128 + 30) == 2^158, which is what Roland
> said.

No, you are wrong.

        2^128*2^30 = 2^158

We are actually dealing with:

        (2^128)^(2^30) = 2^(128*2^30) = 2^(2^37) = 2^137438953472
               ^--- notice the minor difference

ALeine
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