On Fri, Apr 05, 2002 at 12:26:48PM -0800, John Refling wrote:
> to avoid listing all, can try:
> 
> #!/bin/sh
> for i in `echo [0-9] [0-9][0-9] [0-9][0-9][0-9] | sort -n`; do
>    echo $i
> done
> 
> pretty sure the "| sort -n" is not needed, but check that
> result of "echo" is in numerical order.

for i in `echo [1-9] [1-9][0-9] [1-9][0-9][0-9] | sort -n`; do

might be nearer the mark...
OTOH the '| sort -n' could feasably be problematical under some
obscure system :-)

	David

-- 
David Laight: david@l8s.co.uk