Subject: Why ?
To: None <tech-kern@netbsd.org>
From: Charu Pakar <charlie007000@yahoo.ca>
List: tech-kern
Date: 02/11/2002 17:02:15
AS a newbie, I am unable to understand why exit1() is
called twice consecutively with different arguments in
sys_execve().
I do understand the need to exit1() in the event of
failure to 'exec', but why is it done twice ?
Thanx in advance
Charu
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Charu Palkar
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Email:charlie007000@yahoo.ca
cpalkar@sympatico.ca
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