On Mon, Nov 26, 2001 at 01:56:08PM -0000, Daniel wrote:
> Do you have to call callout_init() before each callout_reset()?
> What will happen if you call callout_init() and pass an already
> initialized callout structure?
No, you only need to call callout_init() once.
--
-- Jason R. Thorpe <thorpej@wasabisystems.com>