Subject: default slice sizes
To: None <firstname.lastname@example.org>
From: Chris Amthor <email@example.com>
Date: 07/30/2004 20:34:02
yes, it's me again and again I've got two probalbly stupid questions
regarding NetBSD's HDD partitioning:
(i) How do I get rid of a disklabel? I mean, how do I really and
entirely remove a disklabel from a certain HDD and can start from
(ii) How the fu^H^H heck does NetBSD calculate the default partition
sizes during a fresh install? Using a 4.x GB HDD and staying with the
default values it installes:
popeye# disklabel -r sd0
# size offset fstype [fsize bsize cpg/sgs]
a: 66010 0 4.2BSD 1024 8192 56 # (Cyl. 0 - 40)
b: 199640 66010 swap # (Cyl. 41 - 164)
c: 8330543 0 unused 0 0 # (Cyl. 0 - 5174*)
g: 8064893 265650 4.2BSD 1024 8192 48 # (Cyl. 165 - 5174*)
popeye# df -k
Filesystem 1K-blocks Used Avail Capacity Mounted on
/dev/sd0a 31964 22489 7876 74% /
/dev/sd0g 3908108 134255 3578447 3% /usr
Of course significant parts of the system live in /usr/, but this way
even downloading the pkgsrc tarball to /tmp/ fails, since it just
filles up the remaining 7.5MB.
What are these default values good for, if sticking to them renders a
fresh system unmaintainable?
And how comes disklabel reports eight partitions? I see four, or a
maximum of seven assuming that the partitions d-f do exist in some
kind of a parallel universe... ;)
Ah, before I forget: I'm talking about NetBSD-1.6.2/sparc, target
system is SS5 with 48MB RAM installed.
Q: How is "SunOS" spelled?
A: As one speaks it. With capital "S-O-S".