Subject: Re: Dynamic linking is go (again)
To: Marcus Comstedt <email@example.com>
From: Jason Thorpe <firstname.lastname@example.org>
Date: 07/03/2003 18:11:58
On Thursday, July 3, 2003, at 01:44 PM, Marcus Comstedt wrote:
> Well, this works, but then how come I don't need the -E flag when I
> link against the shared object? That is, if I do
> gcc -o prog foo.o -R. bar.so
> then bar can access the symbols in foo without -E, but if I instead
> dlopen() bar.so from foo, -E is needed. I think the semantics should
> the same for these two cases, if I specify RTLD_GLOBAL to dlopen()...
I think in this case you're simply linking a PIC object directly into
the executable, right? It's not actually recording a dependency on
bar.so in the binary, is it?
-- Jason R. Thorpe <email@example.com>