I should preface this by stating that I know very little about programming and
this is just an idea I would like to implement. I could be totally wrong about
how to do it though.

Wouldn't it be possible to implement this patch with an ifdef?


--- /usr/src/sys/arch/hpcarm/hpcarm/hpc_machdep.c-dist  2003-04-16
08:01:02.000000000 -0400
+++ /usr/src/sys/arch/hpcarm/hpcarm/hpc_machdep.c   2003-04-16
08:01:25.000000000 -0400
@@ -319,7 +319,7 @@
     * XXX kill bootconfig and directly call uvm_physload
     */
    bootconfig.dram[0].address = 0xc0000000;
-   bootconfig.dram[0].pages = 8192;
+   bootconfig.dram[0].pages = 16384;
    bootconfig.dramblocks = 1;
    kerneldatasize = (u_int32_t)&end - (u_int32_t)KERNEL_TEXT_BASE;
 

This is a patch by Ignatios Souvatzis to enable all 64 MB of RAM on a Jornada
728. Michael W. Lucas posted this to the list. Wouldn't the following work?
(Disclaimer: I really don't know what I am talking about but it looks good in
theory.)


    bootconfig.dram[0].address = 0xc0000000;
    #ifdef JORNADA728
    bootconfig.dram[0].pages = 16384;
    #else
    bootconfig.dram[0].pages = 8192;
    #endif
    bootconfig.dramblocks = 1;
    kerneldatasize = (u_int32_t)&end - (u_int32_t)KERNEL_TEXT_BASE;


In the kernel config you would have:

options JORNADA728

Then this would theoretically enable all 64 MB of RAM. Am I even on the right
track at all?

I would just like to have a more permanent solution to the 64 MB issue. Thank
you for your time.

Bryan