>Number:         3509
>Category:       misc
>Synopsis:       bug in bootpd.8
>Confidential:   no
>Severity:       non-critical
>Priority:       low
>Responsible:    misc-bug-people (Misc Bug People)
>State:          open
>Class:          doc-bug
>Submitter-Id:   net
>Arrival-Date:   Thu Apr 17 13:35:02 1997
>Last-Modified:
>Originator:     SAITOH Masanobu
>Organization:
>Release:        latest -current
>Environment:
System: NetBSD ifree.spa.is.uec.ac.jp 1.2D NetBSD 1.2D (IFREE) #38: Mon Apr 7 17:41:09 JST 1997 msaitoh@ifree.spa.is.uec.ac.jp:/var/sources/src/sys/arch/i386/compile/IFREE i386


>Description:
	Try "man bootpd":

 >        -t timeout
 >               Specifies the timeout value  (in  minutes)  that  a
 >               bootpd  or  bootpgw  process  will wait for a BOOTP
 >               packet before exiting.  If no packets are  recieved
 >               for timeout seconds, then the program will exit.  A
		             *******

 This is not "seconds" but "minutes".


>How-To-Repeat:
	man bootpd
>Fix:
	Apply following patch:
--- bootpd.8.orig	Tue Oct 15 01:59:48 1996
+++ bootpd.8	Fri Apr 18 05:27:14 1997
@@ -114,7 +114,7 @@
 process will wait for a BOOTP packet before exiting.
 If no packets are recieved for
 .I timeout
-seconds, then the program will exit.
+minutes, then the program will exit.
 A timeout value of zero means "run forever".
 In standalone mode, this option is forced to zero.
 .TP

>Audit-Trail:
>Unformatted: