>         /*
>          * Unary operators don't require spaces, binary operators do. Don't
>          * use parenthesis unless they're required for precedence, or the
>          * statement is really confusing without them.
>          */
>         a = b->c[0] + ~d == (e || f) || g && h ? i : j >> 1;
> 
>   Can _anyone_ parse that in 5 seconds or less, or should
> the comment and the example be changed/updated?  :)

This, I would say, is bogus.   The phrase "eschew obfuscation" comes
to mind...

			       _MelloN_