>     Finally, escaping $ in sh seems to have busted.  The following 
> line which used to work now tries to map to arg 6.  It may be a POSIX thing
> but it works under bash.  It only shows up with double escapes and 
> recursive shells.  This shows up in a script when trying to pass something
> like foo=`awk " print { \\$6 }" `, but is easily illustrated with the
> following example:

It's not a POSIX thing, bash is much closer to POSIX.2 compliant than we 
we are.  It's just plain broken.

I'll look into it tomorrow.

	--jtc

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