On Mon, Nov 26, 2001 at 01:56:08PM -0000, Daniel wrote:
> Hi
> 
> Do you have to call callout_init() before each callout_reset()?

No, you need to call callout_init() only once for each callout.

> What will happen if you call callout_init() and pass an already
> initialized callout structure?

I guess it's reinitialised back to original state. The callout running
may be lost.

--
Manuel Bouyer, LIP6, Universite Paris VI.           Manuel.Bouyer@lip6.fr
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