Re: strtoll question

[Matt Thomas <matt%3am-software.com@localhost>]

On Sep 14, 2014, at 9:35 PM, Emmanuel Dreyfus <manu%netbsd.org@localhost> wrote:

> Hello
> 
> Consider the program below and its output. Am I using strtoll() wrongly,
> or is this a bug? (this is netbsd-7 branch)
> 
> $ cat /tmp/x.c
> #include <stdio.h>
> #include <errno.h>
> #include <sys/types.h>
> 
> int
> main(void)
> {
>        const char *ptr = "999999999999999";
>        char *endp;
>        long long int res;
> 
>        errno = 0;
>        res = strtoll(ptr, &endp, 0);
>        printf("errno = %d\n", errno);
>        printf("*endp = 0x%02x\n", *endp);
>        printf("str %s\n", ptr);
>        printf("num %lld\n", res);
> 
>        return 0;
> }
> 
> $ cc -o /tmp/x /tmp/x.c 
> $ /tmp/x
> errno = 0
> *endp = 0x00
> str 999999999999999
> num -1530494977

No.  You have no prototype for strtoll in scope.

(gdb) print (int) 999999999999999
$1 = -1530494977

You are missing #include <stdlib.h>

-Wall is your friend.

a.c:14:8: warning: implicit declaration of function 'strtoll' 
[-Wimplicit-function-declaration]
        res = strtoll(ptr, &endp, 0);