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Re: rfc: vmem(9) API/implementation changes
On Wed, 27 Jul 2011, David Young wrote:
> On Wed, Jul 27, 2011 at 04:58:23PM +0000, Eduardo Horvath wrote:
> > On Wed, 27 Jul 2011, David Young wrote:
> >
> > > There are a couple of changes to the API that I would like to make.
> > > First, I don't think that vmem_addr_t 0 should be reserved for error
> > > indications (0 == VMEM_ADDR_NULL), but the API should change from
> > > this:
> >
> > I'd recommend returning -1 on error. 0 is a valid address, but while -1
> > is a valid address, when do you ever use this interface to allocate
> > something that starts at address -1? And it gets around all the noxious
> > problems involved in returning data through reference parameters.
>
> I don't know. Suppose sizeof(vmem_addr_t) == sizeof(uint32_t). Which
> of these cases should fail, and on which statement?
>
> Case A:
>
> 1 vm = vmem_create("test", 0xffffffff, 1, 0, NULL, NULL, NULL, 1,
> 2 VM_SLEEP, IPL_NONE);
> 3 p = vmem_alloc(vm, 1, VM_SLEEP);
>
> Case B:
>
> 1 vm = vmem_create("test", 0xfffffffe, 2, 0, NULL, NULL, NULL, 1,
> 2 VM_SLEEP, IPL_NONE);
> 3 p = vmem_alloc(vm, 2, VM_SLEEP);
>
> Case C:
>
> 1 vm = vmem_create("test", 0xfffffffe, 2, 0, NULL, NULL, NULL, 1,
> 2 VM_SLEEP, IPL_NONE);
> 3 p = vmem_alloc(vm, 1, VM_SLEEP);
> 4 q = vmem_alloc(vm, 1, VM_SLEEP);
All of them should fail in all the routines since you're specifying a
quantum of 0. This means you can only allocate multiples of 0 items from
the list.
OTOH, how many times have you seen code like this:
foo(vmem_t *v) {
void *p;
vmem_alloc(v, 52, 0, (vmem_addr_t *)&p);
....
which has implementation defined functionality.
Eduardo
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