Subject: Re: Why ?
To: Charu Pakar <firstname.lastname@example.org>
From: Bill Studenmund <email@example.com>
Date: 02/11/2002 15:38:54
On Mon, 11 Feb 2002, Charu Pakar wrote:
> AS a newbie, I am unable to understand why exit1() is
> called twice consecutively with different arguments in
> I do understand the need to exit1() in the event of
> failure to 'exec', but why is it done twice ?
Not sure, but from looking at the code, one of the times is sending teh
SIG_ABRT signal, the other is actually killing the process.