AS a newbie, I am unable to understand why exit1() is
called twice consecutively with different arguments in
sys_execve().

I do understand the need to exit1() in the event of
failure to 'exec', but why is it done twice ?

Thanx in advance

Charu
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Charu Palkar
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Email:charlie007000@yahoo.ca
      cpalkar@sympatico.ca

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