On Mon, Nov 26, 2001 at 01:56:08PM -0000, Daniel wrote: > Do you have to call callout_init() before each callout_reset()? > What will happen if you call callout_init() and pass an already > initialized callout structure? No, you only need to call callout_init() once. -- -- Jason R. Thorpe <thorpej@wasabisystems.com>