I will just point out here that using a union { int foo; char bar[4]; }
is using a machine-specific trick.  In fact, any reference to one member
of a union after another has been written to is compiler-specific.

Of course, it'll probably work.

The "correct" (language lawyer) way to do it

	((char *)&intval)[N] = 1;

is a bit more disturbing, but is actually guaranteed to work.

-s