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On Wed, Apr 26 2006 - 08:29, Jeremy C. Reed wrote:
> On Wed, 26 Apr 2006, Joel CARNAT wrote:
>=20
> >    pure_ftpd_flags=3D"-4 -A -e"
>=20
> This looks correct.
>=20
> > But pure-ftpd is still started with no flags.
> > Debugging the start script process, I think I use the right command:
> >    + eval 'rc_flags=3D$pure_ftpd_flags'
> >    ++ rc_flags=3D'-4 -A -e'
>=20
> With your debugging do you also see the line that runs it? (It should als=
o=20
> have a -B at the end.)
>=20

hum... yes:
Starting pure_ftpd.
+ '[' -n '' ']'
+ _doit=3D'/usr/pkg/sbin/pure-ftpd -4 -A -e -B'
+ '[' -n '' ']'
+ eval /usr/pkg/sbin/pure-ftpd -4 -A -e -B
++ /usr/pkg/sbin/pure-ftpd -4 -A -e -B
+ eval
+ return 0

# ps -auxw | grep -i ftp
root   7329  0.0  0.6  204  1120 ?       Is    6:36PM 0:00.00 pure-ftpd: -p=
ure-ftpd (SERVER)=20

indeed, netstat indicates my server only listens of port=3D21 for IPv4...
I didn't thought about checking previously... only looked at ps results - s=
orry.

Would the "daemonize" flag hide the starting flags from process status ?

	Jo

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