Michael Gorsuch wrote:
> Hey all, I'm trying to find the right Unix tool to print out a matched
> regular expression, not just a line that matches.
>=20
> For example,
>=20
> echo [1234] | egrep \(1234\)
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> It matches the expression, but I only want to print the match, '1234'.
>=20
> Any ideas?  I'm sure there's a unix tool I'm not using properly here...=

>=20

Would this work for you?

echo '[1234]' | sed 's/[^[:digit:]+]//g'

I had troubles getting backreferences work as i didn't find any good
examples and the documentation (re_format/regex). This was using FreeBSD
6.1 "sed" so YMMV.

In ultraedit (windows app) i would do this:

input:		[1234]
replace:	^[^\d](\d+)[^\d]$
with:		\1
result:		1234

--=20
Sten Daniel S=F8rsdal