On Tue, 28 Dec 2004, Jason M. Leonard wrote:

>
>
> On Wed, 29 Dec 2004, Florian Stoehr wrote:
>
>> On Tue, 28 Dec 2004, Jason M. Leonard wrote:
>> 
>>> 
>>> 
>>> On Wed, 29 Dec 2004, Florian Stoehr wrote:
>>> 
>>>> Hi,
>>>> 
>>>> the follwing will run with bash, but not with /bin/sh. How to write the 
>>>> increment statement so that /bin/sh will like it? I played around with 
>>>> "let" but without success.
>>>> 
>>>> #!/bin/sh
>>>> i=1
>>>> while [ $i -le $1 ]
>>>> do
>>>> 	echo "Run " $i
>>>> 	i=$[$i+1]  <--- bash can do that, not /bin/sh
>>>> done
>>> 
>>> let i=$((i+1))
>>> 
>>> 
>> 
>> Hm ... as I said, I tried that with let and I did it as in sh(1) with 
>> $((expr)), but it doesn't seem to work:
>> 
>> #!/bin/sh
>> i=1
>> while [ $i -le $1 ]
>> do
>> 	echo "Run " $i
>> 	let i=$((i+1))
>> done
>> 
>> 
>> Gives:
>> 
>> flo@irina [/tmp] # ./test.sh 5
>> Run  1
>> ./test.sh: arith: syntax error: "i+1"
>> 
>> ???
>> 
>> -Flo
>
> Something hates you?  The same code, copy and pasted from your email:
>
> lorax:~ fuzz$ ./test.sh 5
> Run  1
> 2
> Run  2
> 3
> Run  3
> 4
> Run  4
> 5
> Run  5
> 6
>
>
> :Fuzz
>

Hehe - maybe :)

It works with Simon's "i=$(($1+1))". It does not with the script I 
posted. Perhaps you symlinked some other shell to /bin/sh ???

-Florian