Subject: Re: cdparanoia under NetBSD?
To: Manuel Bouyer <firstname.lastname@example.org>
From: B. James Phillippe <email@example.com>
Date: 01/05/2002 11:15:25
On the cold day of Jan 5, Manuel Bouyer mused:
> On Sat, Jan 05, 2002 at 12:53:10AM -0800, B. James Phillippe wrote:
> > Hello Malcolm,
> > Try "-g /dev/rcd0g". I'm a NetBSD newbie, but I recently got
> > cdparanoia working using /dev/rcd0c, and my SCSI drive is on scsibus0
> > target 2 lun 0, so I am guessing* that the letter of the raw scsi
> > device corresponds to the target number. The minor number of the
> > device node would seem to back this guess.
> No it doesn't work that way: device number are assigned when devices are
> found: cd0 is the first cd drive found, cd1 the second, etc ... it's not
> hardwired to SCSI IDs.
This makes sense. But when using a SCSI generic device, how does one
determine which device node to use? I have only one CD-ROM drive in my
system (NetBSD/alpha 1.5.2). The drive is a SCSI CD/R/RW drive. On
bootup, this is what I see:
cd0 at scsibus0 target 2 lun 0: <YAMAHA, CRW2100S, 1.0N> SCSI2 5/cdrom removable
When I use cdparanoia, the only device node that I was able to get it
working with was "/dev/rcd0c". I understand the "rcd0" part; that is (r)aw
(cd) device (0). But why "c" rather than "a" or "b"? The (hypothetical)
example on www.netbsd.org shows this command:
$ cdparanoia -g /dev/rcd0d 2 track-02.wav
Of course, "/dev/rcd0d" did not work for me. I tried "a" and it didn't
work either. Trial and error found that "c" did work. What is the
determining factor in knowing which device node to use?
# bryanxms at ecst dot csuchico dot edu
# Software Engineer