Someone else has already answered you (and my knowledge of qt is quite
limited).  However, I do know C.  You asked whether sizeof knew the size
of your resized array.  The answer is: NO.

sizeof is a _compile_time_operator_, not a function.  It also works
strictly on type information.


At the risk of beating a dead horse:

  int integers [32];
  int *ints = integers;

  printf ("Size of {integers} == %d\n"
          "Size of     {ints} == %d\n",
          sizeof (integers), sizeof (ints) );

On a typical 32-bit system, the first %d will be 128; the second will be 4
(your actual mileage may vary).  That's because the compiler can locally
see that {integers} is an array of fixed size, but about {ints} it only
knows that it's a pointer; it has no idea how much memory is associated
with {ints}.  (Alright, in this trivial example, it could analyze the
program flow and since {ints} isn't {volatile}...but the C standard
doesn't let the compiler be that clever, as far as I know.)


  "I probably don't know what I'm talking about."  --rkr@rkr.kcnet.com