Hi,

This seems simple but the result is obviously wrong. I may be too tired
and making stupid mistakes.

Got it! I forgot to include stdlib.h but why did it not complain that atof
was implicitely defined? Instead, it quietly does the wrong thing.


#include <stdio.h>
#include <math.h>
int main( int argc, char *argv[] )
{
    double x;		/* the decimal */

    argc--; argv++;	/* skip command name */
    if ( argc == 0 ) {
	return 1;
    }
    if ( argc == 1 ) {
	printf ( "argv[0] is \"%s\"\n", argv[0] );
	x = atof( argv[0] );
    } else {
	return 1;
    }
    printf ( "x = %10.8f\n", x ); /* */
    return 0;
}

Result is

argv[0] is "0.123"
x = 3.00000000

-- 
Claude Marinier, Information Technology Group    claude.marinier@dreo.dnd.ca
Defence Research Establishment Ottawa (DREO)    (613) 998-4901  FAX 998-2675
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