Darren Reed wrote:
> 
> "log" at the start of a line means that is what you want to do with the
> packet - which is not a pass and is thus an implicit block.
> 
> What you probably want to do is:
> 
> pass in log all
> 
> which will pass all inbound packets and log them as well.
> 
> Darren


Absolutely! Thank you,

 Patrick