In some mail I received from Patrick Welche, sie wrote
> 
> Adding to my previous post, with
> 
> pass in all
> pass out all
[...]
> log in all
[...]
> log out all

"log" at the start of a line means that is what you want to do with the
packet - which is not a pass and is thus an implicit block.

What you probably want to do is:

pass in log all

which will pass all inbound packets and log them as well.

Darren