Subject: Re: port-i386/21436: i386 boot blocks can not be compiled with proper keymap
To: None <email@example.com>
From: David Laight <firstname.lastname@example.org>
Date: 05/29/2003 09:15:45
On Sat, May 17, 2003 at 11:53:23AM +0100, David Laight wrote:
> > Booting an i386 with a non-US keyboard layout gives you the wrong keyboard
> > mapping at the "boot" prompt.
> The i386 bootblocks actually depend on the BIOS getting the keyboard
> layout right. It doesn't, in itself, do a scancode => ascii translation.
> I agree that there could be serious problems especially on an azerty keyboard.
> I might think about doing something about it.
> Maybe just map the ascii codes about!
> I'll check how my uk keyboard behaves later.
The PC bios assumes a US layout - but does have translations for the keys
that are on a UK keyboard, but not on a US one (eg the |\ key by Z).
Does anyone know which keyboard is worse? and how many keys are wrong?
(in order to generate characters 0..0x7f)
I think it is adequate  to push all the keyboard data through:
p = strchr(keymap, c);
c = p;
with appropriate keymap - IIRC for the uk it is @"@
But I need to know how much space to reserve - is 16 bytes enough?
 the function keys all generate a 0 byte, not an escape sequence
so aren't messed with.
David Laight: email@example.com