On Thu, Aug 08, 2002 at 10:12:36AM -0400, Andrew Brown wrote:
> >I meant
> >
> >    ! :
> >    for f in $? `echo $?` $? `echo $?`
> >    do
> >	    echo $f
> >    done
> >
> >Anyone any idea where the `echo $?` gets its value from?
> >That code outputs 1 0 1 0!
> 
> my guess would be that since the `` bits execute in subshells which
> haven't had any children exit yet, the only reason thing they can
> print would be 0.

but:
	echo $(echo $?)
should output the same as:
	echo $?

	David

-- 
David Laight: david@l8s.co.uk