>> [...TCP doesn't do OOB...], and the BSD way of doing it is a major
>> hack.  The only way to do this correctly withing the TCP spec is to
>> use a second connection for transmitting OOB data.

> Since you are now declaring an explicit second connection, doesn't
> that mean the data is no longer out-of-band?

It _is_ out-of-band with respect to the first connection, which is what
you're after.

					der Mouse

			    mouse@collatz.mcrcim.mcgill.edu